5b^2+-5b-1=0

Solution for 5b^2+-5b-1=0 equation:

5b^2+-5b-1=0

We add all the numbers together, and all the variables

5b^2-5b=0

a = 5; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·5·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*5}=\frac{0}{10}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*5}=\frac{10}{10}
=1
$